Explanation:
Use FOIL, first outside inside last
2x × 2x = 4x^2
2x × 3 = 6x
1 × 2x = 2x
1 × 3 = 3
![4 {x}^(2) + 8x + 3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1fu0wifloue00xnbhwox21evzcq9jxn07f.png)
The formula to find the minimum or maximum value is
![x = ( - b)/(2a)](https://img.qammunity.org/2020/formulas/mathematics/high-school/y308cdqqmu9aprn5vacwghzmcy66bd5vgc.png)
And remember it's always ax^2 + bx + c
So now just plug in the numbers
![( - 8)/(2(4))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4no233wfs5vs9jva9euttvqivvy08e5z8h.png)
-8/8 = -1
If a > 0 then the graph is upwards, in this case 4>0 so it is upwards. And -1 is the vertex, which is the minimum value