63.0k views
0 votes
Which is the intersection of the sets R={0, 1, 2, 4}, S={4, 9, 12, 13}, T={13, 15, 19, 20}?

A {4}
B null set
C {13}

2 Answers

6 votes

Answer:


R\cap S\cap T= \{ \} \text{ or } \phi \text{ aka null/empty/void set}

since there is no common element in all the three sets.

since intersection is associative,

you can do it in simpler ways as:


L \cap (R \cap T) = \{0,1,2,3,4\}\cap\left(\{4,9,12,13\}\cap\{13,15,19,20\}\right) \\ =\{0,1,2,3,4\}\cap(\{13\} = \phi

or


(L \cap R) \cap T = \left(\{0,1,2,3,4\}\cap\{4,9,12,13\}\right)\cap\{13,15,19,20\} \\ =\{4\}\cap(\{13,15,19,20\} = \phi

User Shcherbak
by
7.5k points
1 vote

Answer:

Null set

Explanation:

4 intersects sets R and S but not T

13 intersects sets S and T but not R

So this would result as a null set.

User Pferrel
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories