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Four math questions

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User Frow
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1 Answer

1 vote

Answer:

4) B)
\displaystyle (8)/(15)

3) A)
\displaystyle (2)/(3) > (2)/(4)

2) C)
\displaystyle (28)/(54)

1) A)
\displaystyle (5)/(22)

Explanation:

4) The numbers 8 and 15 have no common divisors other than 1. Answer choice D) has a common divisor of 13, C) has a common divisor of 4, and A) has a common divisor of 5.

3) In this case, since the numerators are equivalent, all we need to do is focus on their denominators. Whenever we have equivalent numerators, the smaller the denominator, the larger the fraction becomes, and so this is the statement we go with.

2) In answer choice D), both denominator and numerator were multiplied by 7, B) was multiplied by 5, and A) was multiplied by 4. Now, C) was never multiplied correctly because the denominator was multiplied by 6 WHILE the numerator was multiplied by 7. This is the answer we go with.

1) We can automatically throw out D) and C) because they go way beyond 3⁄11. Answer choice B) is an equivalent fraction of 3⁄11 because both denominator and numerator were multiplied by 2, leaving the only possible answer of A). Besides, whenever we have a one-term-numerator range difference like 3⁄11 and 2⁄11, we double the denominator and pick the numerator term that is the SUM of the two given numerators in your exercise, which is what you see here:


\displaystyle 5 = 3 + 2

So, 5 is your numerator.

I am joyous to assist you anytime.

User Shadowmatter
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