Question

A cylinder has a radius of 2 inches and a height of 5 inches. A sphere has a

radius of 2 inches. What is the difference between the volumes, to the
nearest tenth of a cubic inch, of the cylinder and the sphere?

Answer 1

`29.3\ in^3`

Explanation:

step 1

Find the volume of the cylinder

we know that

The volume of the cylinder is equal to

`V=\pi r^(2) h`

we have

`r=2\ in\\ h=5\ in`

substitute

`V=\pi (2^(2))(5)`

`V=20\pi\ in^3`

step 2

Find the volume of the sphere

The volume of the sphere is equal to

`V=(4)/(3)\pi r^(3)`

we have

`r=2\ in`

substitute

`V=(4)/(3)\pi (2)^(3)`

`V=(32)/(3)\pi\ in^3`

step 3

Find the difference of volumes

`20\pi\ in^3-(32)/(3)\pi\ in^3=(28)/(3)\pi\ in^3`

assume

`\pi =3.14`

substitute

`(28)/(3)(3.14)=29.3\ in^3`