Question

Unpolarized light of intensity 400 W/m2 is incident on two ideal polarizing sheets that are placed with their transmission axes perpendicular to each other. An additional polarizing sheet is then placed between the two, with its transmission axis oriented at 30∘ to that of the first.

Answer 1

Answer: 300 W / m2

Step-by-step explanation:

Applying Malus' law, the intensity after going through the second polarizer is:

S2 = S1 cos^2 (30) = 400 (0.86)^2 = 400 (0.75) = 300 W / m2.

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