Question

An unknown substance changes temperature from 22°C to 76°C. The substance is also known to have a specific heat of 3.6 kJ/kg °C and mass 5.6 kg. How much heat was transferred in this process? Let (+) indicate that heat is being added to the substance and (-) indicate that heat is being taken from the substance.

Answer 1

the heat transferred in the process was Q = +1088.64 kJ, since Q is positive, heat is being added to the substance

Step-by-step explanation:

the amount of heat exchanged will be

Q = m * c * ( T final - T inicial )

where

m = mass = 5.6 Kg

c= specific heat = 3.6 kJ/kg °C

T final = final temperature = 76°C

T initial = initial temperature = 22°C

therefore

Q = m * c * ( T final - T inicial ) = 5.6 Kg * 3.6 kJ/kg °C * ( 76°C - 22°C) = 1088.64 kJ

Q = +1088.64 kJ

Since Q is positive (+) , heat is being added to the substance (that is why the temperature increases)