125k views
0 votes
Quadratic function help?

Quadratic function help?-example-1
User Etech
by
7.3k points

1 Answer

2 votes

Answer:

12 units

Explanation:

Let the equation of the parabola is
y = (1)/(48) x^(2)

So,
x^(2)  = 48y ........... (1)

Now, the general form of a parabola having vertex at origin and axis parallel to positive y-axis is given by


x^(2)  = 4ay ........ (2)

Now, comparing equation (1) and equation (2) we get, a = 12

We know that the focal length of the parabola
x^(2)  = 4ay i.e. distance between the vertex and the focus is a.

Therefore, the focal length of the parabola (1) is 12 units. (Answer)

User Aviro
by
6.8k points