Answer:
on rearranging,
now, 109-7q should be a multiple of 5,
and for that, 7q must end with 9 or 4 as unit digit.
as q is prime,
let's try q=2,
(109-7×2)/5=95/5=19
which is a prime.
hence, P=19 and Q=2
we got lucky.
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