Question

1. The red light associated with the aurora borealis is emitted by excited oxygen atoms. This

light has and energy wave that has a wavelength that measures 630.0 nm.
a. What is the frequency of the light?
b. What is the energy in joules that is emitted ?
Convert to kilojoules?

Answer 1

Frequency = 0.005× 10¹⁷ s⁻¹

E = 0.03 × 10⁻²⁰KJ

Step-by-step explanation:

Given data:

Wavelength of light = 630.0 nm (630 × 10⁻⁹ m)

Frequency of light = ?

Energy in joule = ?

Solution:

speed of light = wavelength × frequency

Frequency = speed of light / wavelength

Frequency = 3 × 10⁸ m/s / 630 × 10⁻⁹ m

Frequency = 0.005× 10¹⁷ s⁻¹

Energy:

E = h. f

E = 6.63× 10⁻³⁴ Kg. m²/s × 0.005× 10¹⁷ s⁻¹

E = 0.03 × 10⁻¹⁷ j

E = 0.03 × 10⁻¹⁷ j×1 kj /1000 j

E = 0.03 × 10⁻²⁰KJ