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The quadrilateral shown is a rhombus. If AB = 17 and AE = 8, what is the measure of BE

User Cytrinox
by
6.2k points

2 Answers

4 votes

Answer:

C) 16

Explanation:

User Yuri Morales
by
5.7k points
4 votes

Answer:


BE=15\ units

Explanation:

we know that

In a rhombus the diagonals are perpendicular

so

The triangle ABE is a right triangle

see the attached figure to better understand the problem

Applying the Pythagoras Theorem to the right triangle ABE


AB^2=AE^2+BE^2

where

AB is the hypotenuse of the right triangle (greater side)

AE and BE are the legs of the right triangle

we have


AB=17\ units\\AE=8\ units

substitute


17^2=8^2+BE^2

solve for BE


289=64+BE^2


BE^2=289-64


BE^2=225


BE=15\ units

The quadrilateral shown is a rhombus. If AB = 17 and AE = 8, what is the measure of-example-1
User Vitalii Vasylenko
by
5.3k points