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Sulfur dioxide is produced in enormous amounts for sulfuric acid production. It melts at - 73˚C and boils at - 10˚C. Its ΔH˚fus is 8.619 kJ/mol and its ΔH˚vap is 25.73 kJ/mol. The specific heat capacities of the liquid and the gas are 0.995 J/g·K and 0.622 J/g·K, respectively. How much heat is required to convert 2.500 kg of solid SO₂ at the melting point to a gas at 60˚C?

User Lloan
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1 Answer

2 votes

Answer:

Heat required to convert 2.500 kg of solid SO₂ at the melting point to a gas at 60˚C is 1,589.724 kilo joules.

Step-by-step explanation:

Heat required to melt sulfur dioxide solid -73˚C =
q_1

Latent heat melting of sulfur dioxide =
\Delta H^o_(fus)=8.169 kJ/mol=8169 J/mol

Mass of sulfur dioxide solid , m= 2.500 kg = 2500 g

Moles of sulfur dioxide solid ,n=
(2500 g)/(64 g/mol)=39.062 mol


q_1=n* \Delta H^o_(fus)


q_1=39.062 mol* 8169 J/mol=319,097.48 J=319.097 kJ

Heat required to raise the temperature of liquid sulfur dioxide from -73˚C to -10˚C =
q_2

-10˚C = 263.15 K, -73˚C = 200.15 K

Mass of sulfur dioxide liquid, m= 2.500 kg = 2500 g

Specific heat of liquid sulfur dioxide =
C_1=0.995 J/g K

Change in temperature =
\Delta T_1=(263.15 K-200.15 K)=63 K


q_2=m* C_1* \Delta T_1


q_2=2500 g* 0.995 J/g K* 63 K=156,712.5 J=156.712 kJ

Heat required to vaporize sulfur dioxide liquid at -10˚C=
q_3

Latent heat melting of sulfur dioxide =
\Delta H^o_(vap)=25.73 kJ/mol=25730 J/mol

Mass of sulfur dioxide liquid, m= 2.500 kg = 2500 g

Moles of sulfur dioxide solid ,n=
(2500 g)/(64 g/mol)=39.062 mol


q_3=n* \Delta H^o_(vap)


q_3=39.062 mol* 25.73 kJ/mol=1,005.065 kJ

Heat required to raise the temperature of liquid sulfur dioxide from -10˚C to 60˚C =
q_4

-10˚C = 263.15 K, 60˚C = 333.15 K

Mass of sulfur dioxide liquid, m= 2.500 kg = 2500 g

Specific heat of gas sulfur dioxide =
C_2=0.622 J/g K

Change in temperature =
\Delta T_2=(333.15 K-263.15 K)=70 K


q_4=m* C_2* \Delta T_2


q_4=2500 g* 0.622 J/gK* 70 K=108,850 J=108.850 kJ

Heat required to convert 2.500 kg of solid SO₂ at the melting point to a gas at 60˚C = Q


Q=q_1+q_2+q_3+q_4


Q=319.097 kJ+156.712 kJ+1,005.065 kJ+108.850 kJ=1,589.724 kJ

User Scorchio
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