Question

Dinitrogen oxygen, N2O, has two double bonds. The general structure is N=N=O. The formal charge on the oxygen atom isA.) 0B.) +1C.) +2D.) -1

Answer 1

A.) 0

Step-by-step explanation:

Dinitrogen oxygen (
`N_2O`)

Valence electrons of oxygen = 6

Valence electron of nitrogen = 5

The total number of the valence electrons = 2(5) + 6 = 16

The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So, The Lewis structure is shown in image below.

Formula for formal charge :

`\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}`

Formal charge for oxygen:

`\text{Formal charge}=6-4-(4)/(2)=0`