Question

Use technology to find the​ P-value for the hypothesis test described below. The claim is that for 12 AM body​ temperatures, the mean is μ >98.6°F. The sample size is n =6 and the test statistic is t=2.528

Answer 1

0.0263

Explanation:

We have the null hypothesis
`H_(0): \mu = 98.6` vs the alternative hypothesis
`\mu > 98.6` (upper-tail alternative). Besides, we have a small sample size n = 6, therefore, if we suppose that
`H_(0)` is true, then, the observed value t = 2.528 comes from a Student's t-distribution with n-1 = 6 - 1 = 5 degrees of freedom. Therefore, the p-value is computed as P(T > 2.528) = 0.0263