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A hypothetical population of 500 cats has two alleles, T and t, for a gene that codes for tail length. The table below presents the phenotype of cats with each possible genotype, as well as the number of individuals in the population with each genotype. Assume that this population is in Hardy-Weinberg equilibrium

a. What is the frequency of cats with long tails in the population?
b. What is the frequency of cats with short tails in the population?
c. What is the frequency of cats that are homozygous dominant in the population?
d. What is the frequency of the T allele in the gene pool of this population?
e. What is the frequency of the t allele in the gene pool of this population?

User Jasmyne
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2 Answers

3 votes

Final answer:

The frequency of cats with long tails and short tails, as well as the frequency of homozygous dominant cats and the frequencies of the T and t alleles in the gene pool, can be determined using the formulas derived from the Hardy-Weinberg equilibrium.

Step-by-step explanation:

To determine the frequencies of the different genotypes, we can use the formulas derived from the Hardy-Weinberg equilibrium.

a. The frequency of cats with long tails (TT and Tt genotypes) can be calculated as p² + 2pq, where p represents the frequency of the T allele. As given, the population is in Hardy-Weinberg equilibrium, so we can assume that p² + 2pq + q² = 1. Since q represents the frequency of the t allele, the frequency of cats with long tails can be found using the formula p² + 2pq = 1 - q².

b. Similarly, the frequency of cats with short tails (tt genotype) can be found using the formula q².

c. The frequency of cats that are homozygous dominant (TT genotype) is equal to p².

d. The frequency of the T allele in the gene pool of this population is equal to p.

e. The frequency of the t allele in the gene pool of this population is equal to q.

User Rick Pat
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5.4k points
1 vote

Answer:0.16

q^2 = 80/500 = 0.16

Step-by-step explanation:

User Kourosh
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4.7k points