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Find m∠FGL.

m∠FGH = 165°

m∠FGL = (x + 15)°

and m∠LGH = (9x)°

A) 20°

B) 25°

C) 30°

D) 35°

Find m∠FGL. m∠FGH = 165° m∠FGL = (x + 15)° and m∠LGH = (9x)° A) 20° B) 25° C) 30° D-example-1

2 Answers

4 votes

Answer:

30 Degrees

C)

Explanation:

m∠FGL + m∠LGH = m∠FGH → (x + 15) + (9x) = 165 → x = 15

Therefore, m∠FGL = x + 15 = 15 + 15 = 30°

User Konqi
by
5.1k points
0 votes

Answer:

C)
\displaystyle 30°

Step-by-step explanation:

Use the Angle Addition Postulate to figure this out:


\displaystyle m∠FGL + m∠LGH = m∠FGH

165° = (x + 15)° + (9x)°

165° = (15 + 10x)°

- 15° - 15°

_____________


\displaystyle (150°)/(10) = ([10x]°)/(10) \\ \\


\displaystyle 15° = x[Plug this back into the modeled expression for the
m∠FGLto get the angle measure of 30°];
\displaystyle 30° = m∠FGL

I am joyous to assist you anytime.

User Nikhil C George
by
6.3k points