Question

For which of the following equations is the change in enthalpy at 25 Celcius and 1 atm pressure equal to ΔHf of CH3OH (l)?A.) CH3OH + 3/2 O2 ---> CO2 + 2H2O (l)B.) CH3OH + 3/2 O2 ---> CO2 + 2H2O (g)C.) 2CH3OH + 3O2 ---> 2CO2 + 4H2O (l)D.) C + 2H2 + 1/2 O2 ---> CH3OH

Answer 1

D. C + 2H₂ + ¹/₂O₂ → CH₃OH

Step-by-step explanation:

The standard enthalpy of formation -ΔHf- is defined as the enthalpy change for the formation of 1 mol of a compound from its component elements.

Component elements are any element in its standard state.

For CH₃OH(l) at 25°C and 1 atm of pressure, the component elements are C(s), H₂(g) and O₂(g)

Thus, the equation that represent the standard enthalpy of formation of CH₃OH(l) is:

D. C + 2H₂ + ¹/₂O₂ → CH₃OH

I hope it helps!