Answer:
The amount would be $ 858.21
Explanation:
Given,
In first account,
Deposited amount,
= $ 500,
Annual simple interest,
= 2.5%,
Number of years,
= 3 years,
So, the amount after 3 years,
![A_1 = P_1 + (P_1* r_1* t_1)/(100)](https://img.qammunity.org/2020/formulas/mathematics/high-school/m6evpw0kdqvnxe08uu4va8666gpjc7jfdn.png)
![A_1 = 500 + (500* 2.5* 3)/(100)](https://img.qammunity.org/2020/formulas/mathematics/high-school/xfwx5qok5r4kwt30ataduewo6pwkpnetiw.png)
![A_1 = 500 + (3750)/(100)](https://img.qammunity.org/2020/formulas/mathematics/high-school/y7b0xqshhx3zttwil7pxgznin1k4r36zzb.png)
![A_1 = 500 + 37.50](https://img.qammunity.org/2020/formulas/mathematics/high-school/xwr2rvjwwvwl7feqe51k3ou8lcdlreoimb.png)
![A_1 = 537.5](https://img.qammunity.org/2020/formulas/mathematics/high-school/cjbow1n2ye75iq3e7wmizvaf8d14jen2an.png)
In second account,
Deposited amount,
= $ 300,
Annual compound interest,
= 2.25%, ( ∵
)
Number of years,
= 3 years,
So, the amount after 3 years,
![A_2 = P_2(1 + (r_2)/(100))^(t_2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/7afmp4idjs73zv3kzkd61pib5aefehzkq7.png)
![A_2= 300(1+(2.25)/(100))^3](https://img.qammunity.org/2020/formulas/mathematics/high-school/cjee5z1m8r7lr5jealgg1esp5o7ivndw16.png)
![A_2 = 300(1+0.0225)^3](https://img.qammunity.org/2020/formulas/mathematics/high-school/herkvsjq7b2f6dckcjgain2cm2aqmgp7e3.png)
![A_2 = 300(1.0225)^3](https://img.qammunity.org/2020/formulas/mathematics/high-school/iagij3n1fcm0sns1in43617xo980afl5p7.png)
![A_2 = 320.71](https://img.qammunity.org/2020/formulas/mathematics/high-school/rcsaal0qx0h63uuztntj63c71cz8r0roul.png)
Hence, the total amount,
![A=A_1 + A_2 = 537.5 + 320.71 = \$ 858.21](https://img.qammunity.org/2020/formulas/mathematics/high-school/s6hge0isgzpz65ww6yjv8hg3aiq76lmduh.png)