Question

Fast Bullets A rifle with that shoots bullets at 420 m/s shoots a bullet at a target 49.8 m away. How high above the target must the rifle barrel be pointed to ensure that the bullet will hit the target?

Answer 1

0.08°

Step-by-step explanation:

velocity of projection, u = 420 m/s

Horizontal range, R = 49.8 m

Let the angle of projection is θ.

Use the formula for the horizontal range.

`R=(u^(2)Sin2\theta )/(g)`

`49.8=(420^(2)Sin2\theta )/(9.8)`

Sin 2θ = .0027

2θ = 0.1585

θ = 0.08°