Question

A weather balloon is inflated to a volume of 28.1 L at a pressure of 745 mmHg and a temperature of 29.0 ∘C. The balloon rises in the atmosphere to an altitude where the pressure is 380. mmHg and the temperature is -16.3 ∘C. Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude.

Answer 1

`V_2=46.8 L`

Step-by-step explanation:

For these changes in pressure and temperature, assuming that the gases in the balloon are ideal, we can apply the general equation of gases:

`(P_1*V_1)/(T_1)=(P_2*V_2)/(T_2)`

Been 1 the initial conditions and 2 the final ones:

`(745 mmHg*28.1L)/(302K)=(380 mmHg*V_2)/(256.7K)`

`V_2=(745 mmHg*28.1L*256.7K)/(380 mmHg*302K)`

`V_2=46.8 L`