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Find all roots: x^3-7x^2-12x = 0

User Shabi
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1 Answer

3 votes

Answer:

The roots are 0, 3 and 4.

Explanation:

x^3-7x^2-12x = 0 Take out x:

x(x^2 - 7x - 12) = 0 Factor the expression in the brackets:

x(x - 3)(x - 4) = 0

x = 0 or x - 3 = 0 or x - 4 = 0, so

The roots are 0, 3 and 4.

User Marius T
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