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When an RL circuit is connected to a battery, which is true about its initial and final states?

A. It initially acts like a broken wire and finally acts like ordinary connecting wire.
B. It initially acts like ordinary connecting wire and finally acts like a broken wire.
C. It acts like broken wire throughout the charging.
D. It acts like ordinary connecting wire throughout the charging.

User Wiseindy
by
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1 Answer

2 votes

Answer:A

Step-by-step explanation:

In R-L circuit current is given by


i=i_0\left [ 1-e^{(-t)/(L/R)}\right ]

where i=current at any time t


i_0=maximum\ current

R=resistance

L=Inductance

at t=0
e^{(-t)/(L/R)} approaches to 1

therefore
i=i_0\left [ 1-1\right ]

i=0

when t approaches to
\infty,
e^{(-t)/(L/R)} approaches to zero

thus
i=i_0

thus we can say that initially circuit act as broken wire with zero current

and it increases exponentially with time and act as ordinary connecting wire

User Eino Gourdin
by
6.3k points