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How much water should be added to 6 gallons of pure acid in order to obtain the 24% acid solution?

HELP

User Jvilalta
by
5.3k points

2 Answers

1 vote

Answer:

19 gallons

Explanation:

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User Nikita Took
by
5.7k points
3 votes

Answer:

19 gallons

Explanation:

Let x gallons be the amount of water which should be added to 6 gallons of pure acid in order to obtain the 24% acid solution.

Amount of water = x gallons

Amount of pure acid = 6 gallons

Amount of acid solution = x + 6 gallons

Amount of acid in acid solution = 24%

So, there are
0.24(x+6) gallons of acid in acid solution.

Hence,


0.24(x+6)=6

Solve this equation. Multiply it by 100:


24(x+6)=600\\ \\24x+144=600\\ \\24x=600-144\\ \\24x=456\\ \\x=19\ gallons

User Huu Bao Nguyen
by
5.3k points