Question

Green checks and red X's are not displayed for the multiple choice portion of this question. In part D of the experiment, a student begins with a beaker containing 10.0 mL of 0.010M HCl solution and adds different volumes of 0.010M NaOH. How many millimoles of acid are initially in the beaker?

Answer 1

0.10 mmol

Step-by-step explanation:

Initially there is only HCl in the beaker. We can calculate the moles of HCl using the following expression:

`M=(n)/(V(L))`

where,

M is the molarity of the solution

n is the moles of the solute

V(L) is the volume of the solution expressed in litres

`M=(n)/(V(L))\\n=M . V(L)= (0.010mol)/(L) .10.0 * 10^(-3) L=1.0 * 10^(-4)mol`

The milimoles of HCl are:

`1.0 * 10^(-4)mol.(10^(3)mmol )/(1mol) =0.10mmol`