Answer: 2moles
Step-by-step explanation:
The best way to solve this problem is to write a balance equation for the reaction.
Which is: Fe2 + 2i2______> 2Fei2
With this you can see that iron ii reacting with excess iodine produces two (2) moles of iron ii iodine.
Alternatively.
Using the formular
Moles = reacting mass/molar mass
Reacting mass = 112g
Molar mass of iron ii = 55g/mol
Hence,
Mole = 112g divides 55g/mol
= 2.0mol//