Answer: 0.8031
Explanation:
Binomial distribution:
For a binomial variable x,
The probability of getting success in x trials =

, where n = Total trials .
p= Probability of getting success in each trial.
For the given situation , we take x as the number of damaged apple .
Given : The proportion of damaged apples : p=0.15
n= 10
Then, the probability that his sample will contain at least one damaged apple. :-
![P(x\geq1)=1-P(x<1)\\\\=1-P(x=0)\\\\=1-^(10)C_(0)(0.15)^0(1-0.15)^(10)\\\\=1-(1)(0.85)^(10)\ \ [\because\ ^nC_0=1]\\=1-0.196874404341=0.803125595659\approx0.8031](https://img.qammunity.org/2020/formulas/mathematics/college/eqz9im2yk0b7yhfv6ab0kj7mnamsud6eti.png)
Hence, the required probability = 0.8031