Answer:
The values of x are -3 and 5
Explanation:
we have
![x-(15)/(x)=2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1szw9ij2dx4cp2sh3uubnpz7055nui09ip.png)
Multiply by x both sides to remove the fraction
![x^(2) -15=2x\\\\x^(2) -2x-15=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v003yjtvornmbfw2z02r11xvd53rewc7gw.png)
The formula to solve a quadratic equation of the form
![ax^(2) +bx+c=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/s7uo0xalxsyf26mt8szqanzqj4u4a8f4lu.png)
is equal to
in this problem we have
![x^(2) -2x-15=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ndbt507q0rzrzaoadfwt8cbzc6a8cukmra.png)
so
substitute in the formula
therefore
The values of x are -3 and 5