Question

how many kilojoules of heat are absorbed when 0.38 grams of chloroethane vaporizes at its normal boiling point?​

Answer 1

1.6 ×10⁻¹ kj

Step-by-step explanation:

Answer 2

1.6 ×10⁻¹ kj

Step-by-step explanation:

Given data:

Mass of chloroethane = 0.38 g

Heat absorbed = ?

Solution:

Molar mass of chloroethane = 64.51 g/mol

Molar heat of vaporization = 26.4 kj/mol

Number of moles:

Number of moles = mass/ molar mass

Number of moles = 0.38 g/ 64.51 g/mol

Number of moles = 0.006 mol

Heat absorbed:

0.006 mol × 26.4 kj/mol

0.16 kj

or 1.6 ×10⁻¹ kj