Answer:
Tension in the string, F = 6.316 N
Step-by-step explanation:
It is given that,
Mass of the Yo - Yo, m = 0.2 kg
Length of the string, l = 0.8 m
It makes a complete revolution each second, angular velocity,

Let T is the tension exist in the string. The tension acting on it is equal to the centripetal force acting on it. Its expression is given by :



F = 6.316 N
So, the tension must exist in the string is 6.316 N. Hence, this is the required solution.