Question

Thermal decomposition of a rail car load of limestone to lime and carbon dioxide requires 2.97 x 106 kJ of heat.

Convert this energy to calories.

Once you have the value, determine its log (base 10).

Answer 1

Answer: a)
`68.3* 10^6cal`

b)
`log_(10)(68.3* 10^6cal)=7.83`

Step-by-step explanation:

Heat is defined as a spontaneous flow of energy from one object to another. It is measured in Joules, calories, kilo Joules etc.

These units of energy are inter convertible.

We are given:

a) Energy absorbed by limestone =
`2.97* 10^6kJ`

Converting this unit of temperature into
`calories` by using conversion factor:

1 kJ = 239.006 calories

`2.97* 10^6kJ=(239.006)/(1)* 2.97* 10^6=68.3* 10^6cal`

Thus the energy in calories is
`68.3* 10^6cal`

b) The value of log base 10 of
`68.3* 10^6cal` is:

`log_(10)(68.3* 10^6cal)=7.83`