Question

A 14.0 L sample of fluorine gas has a pressure of 29.0 atm at a certain temperature. At the same temperature, what volume would this gas occupy at a pressure of 2.90 atm? Assume ideal behavior. V=

Answer 1

The volume occupied by the gas at a pressure of 2.90 atm = 140L

Step-by-step explanation:

Since we are assuming ideal behavior, the gas equation is:

pV = nRT

where, p is the pressure

V is the volume

R is the universal gas constant

T is the temperature

The temperature is constant. We can use the Boyle's Law:

`p_(1)V_(1)=p_(2)V_(2)`

`V_(2)=(p_(1)V_(1) )/(p_(2))` -----(1)

`p_(1)=29.0` atm

`V_(1)=14L`

`p_(2)=2.90` atm

`V_(2)=(29.0*14)/(2.90)`=
`140L`

Therefore, at the same temperature, the volume occupied by the gas at a pressure of 2.90 atm is 140L.