Final answer:
To throw a baseball into a circular orbit just above the surface of Deimos and have it return to you, you would need to throw it with the escape velocity, which is approximately 13.95 m/s.
Step-by-step explanation:
To throw a baseball into a circular orbit just above the surface of Deimos and have it return to you, you would need to throw it with the escape velocity. The escape velocity is the minimum velocity required for an object to overcome the gravitational pull of a celestial body. On Deimos, the escape velocity can be calculated using the formula:
V = sqrt((2 * G * M) / R)
where V is the escape velocity, G is the gravitational constant (approximately 6.674 x 10^-11 N(m/kg)^2), M is the mass of Deimos (1.5 x 10^15 kg), and R is the radius of Deimos (diameter/2 = 6 km).
Plugging in the values, the escape velocity comes out to be approximately 13.95 m/s.