Question

For a moving object, the force acting on the object varles directly with the object's acceleration. When a force of 25 N acts on a certain object, the acceleration

of the object is 5 m/s. If the acceleration of the object becomes 9 m/s', what is the force?​

Answer 1

`\Huge{\underline{\underline{\mathfrak{Answer \colon}}}}`

According to the Question,

`\large{\sf{ f \propto \: a}}`

From the Question,

• Initial Acceleration,a = 5 m/s²

• Force at a = 5 m/s²,f = 25 N

• Final Acceleration,A = 9 m/s²

To find

Force exerted on the object at a = 9 m/s²

We Know that,

`\huge{\boxed{ \boxed{ \sf{f = ma}}}}`

Firstly,we need to find the mass of the object

Thus,

`\sf{m = (f)/(a) } \\ \\ \implies \: \sf{m = (25)/(5) } \\ \\ \huge{ \implies \: \sf{m = 5 \: kg}}`

Now,

`\sf{F = mA} \\ \\ \implies \: \sf{F = (5)(9)} \\ \\ \huge{ \implies \: \sf{F = 45 \: N}}`