Answer:
(a) The cost of 1 model house A = $24
(b) YES, with $200 Victor can purchase 3 A model & 4 B model houses.
Explanation:
Let us assume the cost of model house B = $ m
So, the cost of model house A =$ ( m - 6)
So, the price of 5 A model house = 5 x ( Rate of 1 model house A)
= 5(m-6)
And, the price of 3 B model house = 3 x ( Rate of 1 model house B)
= 3 x (m) = 3 m
So, the cost of 3 B house + 5 A house = 5(m-6) + 3 m
⇒5(m-6) + 3 m = $210
or, 5 m - 30 + 3 m = 210
or, 8 m = 240
or, m = 30
So, the cost of 1 B house = m = $30
And the cost of 1 house A = (m -6) = (30 - 6) = $24
Now, The cost of 3 A model + 4 B model
= 3( 24) + 4(30) = 72 + 120 = 192
So, The cost of 3 A model + 4 B model = $192 and $192 < $200
Hence, YES, with $200 Victor can purchase 3 A model + 4 B model houses.