Answer:
2x^3 + 3x^2 - 11x - 6.
Explanation:
(2x+1) (x-2) (x+3)
= (2x + 1)[x(x + 3)-2(x + 3)]
= (2x + 1)(x^2 + x - 6)
= 2x(x^2 + x - 6) + 1(x^2 + x - 6)
= 2x^3 + 2x^2 - 12x + x^2 + x - 6
= 2x^3 + 3x^2 - 11x - 6.
Good morning,
= (2x+1) [(x-2) (x+3)]
= (2x+1) [x²+3x-2x-6]
= (2x+1) [x²+x—6]
= 2x³+2x²-12x+x²+x-6
=2x³+3x²-11x-6.
:)
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