Question

Find the cotangent of both angle A and angle B.



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Answer 1

`\displaystyle (5)/(12) = cot∠B \\ 2(2)/(5) = cot∠A`

Explanation:

`\displaystyle (OPPOSITE)/(HYPOTENUSE) = sin\:θ \\ (ADJACENT)/(HYPOTENUSE) = cos\:θ \\ (OPPOSITE)/(ADJACENT) = tan\:θ \\ (HYPOTENUSE)/(ADJACENT) = sec\:θ \\ (HYPOTENUSE)/(OPPOSITE) = csc\:θ \\ (ADJACENT)/(OPPOSITE) = cot\:θ \\ \\ (10)/(24) = cot∠B → (5)/(12) = cot∠B \\ \\ (24)/(10) = cot∠A → 2(2)/(5) = cot∠A`

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Answer 2

Answer: tangent of A = 2.4

Cotangent of B = 0.4167

Explanation: