Question

Find the secant of both angle A and angle B.

Answer 1

`\displaystyle 2(3)/(5) = sec∠B \\ 1(1)/(12) = sec∠A`

Explanation:

`\displaystyle (OPPOSITE)/(HYPOTENUSE) = sin\:θ \\ (ADJACENT)/(HYPOTENUSE) = cos\:θ \\ (OPPOSITE)/(ADJACENT) = tan\:θ \\ (HYPOTENUSE)/(ADJACENT) = sec\:θ \\ (HYPOTENUSE)/(OPPOSITE) = csc\:θ \\ (ADJACENT)/(OPPOSITE) = cot\:θ \\ \\ (26)/(10) = sec∠B → 2(3)/(5) = sec∠B \\ \\ (26)/(24) = sec∠A → 1(1)/(12) = sec∠A`

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Answer 2

The Secant of angle A is 1.083 and

The Secant of angle B is 2.6

Explanation:

Given as : The figure is shown as right angle triangle, right angle at c

the measure sides as

Hypotenuse = AB = 26 unit

Base = AC = 24 unit and

Perpendicular = BC = 10 unit

Now, ∵ Sec Ф =
`(\textrm Hypotenuse)/(\textrm Base)`

So, From triangle

Sec A =
`(\textrm Hypotenuse)/(\textrm Base)`

Or, Sec A =
`(\textrm AB)/(\textrm AC)`

Or, Sec A =
`(\textrm 26)/(\textrm 24)`

∴ Sec A = 1.083

Again ,

Sec B =
`(\textrm Hypotenuse)/(\textrm Base)`

Or, Sec B =
`(\textrm AB)/(\textrm BC)`

Or, Sec B =
`(\textrm 26)/(\textrm 10)`

∴ Sec B = 2.6

Hence The Secant of angle A is 1.083 and

The Secant of angle b is 2.6 Answer