Question

A student pushes a 21-kg box initially at rest, horizontally along a frictionless surface for 10.0 m and then releases the box to continue sliding. If the student pushes with a constant 10 N force, what is the box's speed when it is released?

Answer 1

Answer:v=3.08 m/s

Step-by-step explanation:

Given

mass of student
`m=21 kg`

distance moved
`d=10 m`

Force applied
`F=10 N`

acceleration of system during application of force is a

`a=(F)/(m)=(10)/(21)=0.476 m/s^2`

using
`v^2-u^2=2 as`

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

`v^2-0=2* 0.476* 10`

`v=√(9.52)`

`v=3.08 m/s`