Question

One of the many reactions which occur when iron ore is smelted in a blast furnace is given below. For this reaction, the equilibrium constant in terms of partial pressures, Kp, is 0.900 at 873 K and 0.396 at 1273 K. Assume the reaction takes place in a vessel containing only product and reactant molecules and that AH and AS do not change with temperature. FeO(s) + CO(g) = Fe(s) + CO2(g) a) Calculate AH, AG and AS for the reaction at 873 K b) What is the mole fraction of CO2(g) at 873 K? Include only the gas-phase species in this mole fraction.

Answer 1

you looking beautiful

Answer 2

Explanation: AH, AG and AS for the reaction at 873 K

delta G =-RT ln Kp

G= -8.314 x 873 ln 0.9

= 764.7J/mol

AG = AH-TAS

AH = 764.7 - 8314(0.9)

Kp =pCO/pCo2

Substitute the values at different temp. Solve simultaneously

Since mole fraction =kp/pCo

Mf =1.5