Answer:
-$0.90
Explanation:
There are only two possible outcomes, winning $23 (W) or losing $15 (L). Therefore:
![P(W) + P(L) = 1](https://img.qammunity.org/2020/formulas/mathematics/college/vil8kg8837ree72re8vy3snub184pdtfrs.png)
The probability of the player making his next 3 free throws (P(W)) is:
![P(W) = (217)/(302)*(217)/(302)*(217)/(302)\\P(W) = 0.37098](https://img.qammunity.org/2020/formulas/mathematics/college/jalvopu0hjyeykaj57zdtg5kjrmg9kiino.png)
The probability of the player NOT making his next 3 free throws (P(L)) is:
![P(L) = 1 - P(W) = 1 - 0.37098\\P(L) = 0.62902](https://img.qammunity.org/2020/formulas/mathematics/college/m0zgerogmw3nd5a59fw2oc160vt2zynbwe.png)
Expected value (EV) is given by the payoff of each outcome multiplied by its probability:
![EV = (23*0.37098) -(15*0.62902)\\EV = -\$0.90](https://img.qammunity.org/2020/formulas/mathematics/college/goncuf4zbaladqw409ns47x30alzbmtezy.png)
The expected value of the proposition is -$0.90