Question

A 20-cm-long spring is attached to a wall. When pulled horizontally with a force of 100 N, the spring stretches to a length of 22 cm. The same spring is now suspended from a hook and a 10.2-kg block is attached to the bottom end. How long is the stretched spring in cm? (Do not include unit in answer)

Answer 1

the length of stretched spring in cm is 22

Step-by-step explanation:

given information:

spring length, x1 = 20 cm = 0.2 m

force, F = 100 N

the length of spring streches, x2 = 22 cm = 0.22 m

According to Hooke's law

F = - kΔx

k = F/*=(x2-x1)

= 100/(0.22 - 0.20)

= 5000 N/m

if the spring is now suspended from a hook and a 10.2-kg block is attached to the bottom end

m = 10.2 kg

W = m g

= 10.2 x 9.8

= 99.96 N

F = - k Δx

Δx = F / k

= 99.96 / 5000

= 0.02

Δx = x2- x1

x2 = Δx + x1

= 0.20 + 0.02

= 0.22 m

= 22 cm