Question

Arrange the following molecules in order of increasing bond angles (smallest first): (A) XeF4.(B) CH4.(C) H2O.(D) BeH2. Enter four letters in order: (e.g. ABCD, DCBA, ACBD, etc.)"

Answer 1

ACBD

Step-by-step explanation:

The bond angles of the given molecules will be:

`XeF_(4)`

Square planar shape

Bond angle = 90°

`CH_(4)` =

Tetrahedral

Bong angle = 109.5°

`H_(2)O` =

Bent shape

Bong angle = 104.5°

`BeH_(2)` =

Linear

Bong angle = 180°

Thus the order will be:

`XeF_(4)` <
`H_(2)O`<
`CH_(4)`<
`BeH_(2)`