Question

A 62 gram sample of Fe-53 decays for 34.04 minutes. What mass of iron remains?

Answer 1

Mass of iron remains : 3.875 g

Further explanation

Given

62 gram sample of Fe-53 decays for 34.04 minutes.

Required

mass of iron remains

Solution

Hal life of Fe-53 = 8.51 min

`\large{\boxed{\bold{N_t=N_0((1)/(2))^{t/t(1)/(2) }}}`

No=62 g

t = 34.04 min

t1/2 = 8.51 min

Input the value :

`\tt Nt=62.(1)/(2)^(34.04/8.51)\\\\Nt=62.(1)/(2)^4\\\\Nt=3.875~g`