Question

Pete slides a crate up a ramp with constant speed at an angle of 24.3 ◦ by exerting a 289 N force parallel to the ramp. How much work has been done against gravity when the crate is raised a vertical distance of 2.39 m? The coefficient of friction is 0.33.

Answer 1

W=972.73 J

Step-by-step explanation:

Given that

θ = 24.3°

F= 289 N

h= 2.39 m

μ = 0.33

Given that velocity is constant is means that acceleration is zero that is why force will be balance.

Lest take mass = m

Gravity force along ramp = m g sinθ

Friction force = μm g cosθ

F= m g sinθ + μm g cosθ

By putting the values

F= m g (sinθ + μcosθ)

289 = 10 m ( sin 24.3°+ 0.33 cos 24.3°) ( take g =10 m/s²)

289 = 10 m(0.71)

m = 40.7 kg

The force against gravity W

W= m g h

W= 40.7 x 10 x 2.39 J

W=972.73 J