Question

A planet has a surface temperature of 95.0 K and an atmospheric pressure of 1.60 atm. If 4.87 L of atmosphere has a mass of 28.6 g, what is the average molar mass of the atmosphere? Use R=0.08206L atmmol K for the gas constant. Your answer should include three significant figures.

Answer 1

M=28.88 gm/mol

Step-by-step explanation:

Given that

T= 95 K

P= 1.6 atm

V= 4.87 L

m = 28.6 g

R=0.08206L atm .mol .K

We know that gas equation for ideal gas

P V = n R T

P=Pressure , V=Volume ,n=Moles,T= Temperature ,R=gas constant

Now by putting the values

P V = n R T

1.6 x 4.87 = n x 0.08206 x 95

n=0.99 moles

We know that number of moles given as

`n=(m)/(M)`

M=Molar mass

`n=(m)/(M)`

`0.99=(28.6)/(M)`

M=28.88 gm/mol