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What is the awnser to the circled equations?​

What is the awnser to the circled equations?​-example-1
User Andi North
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1 Answer

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Answer:


y = - (1)/(3)x - 1

Explanation:

We have to write an equation of a line which passes through the given point (-9,2) and is perpendicular to the given straight line y = 3x - 12 ........... (1)

Now, equation (1) is in the slope-intercept form and the slope of the line is 3.

Let, m is the slope of the required line.

So, 3m = -1

{Since, the product of the slopes of two perpendicular straight lines is -1}


m = - (1)/(3)

Therefore, the equation of the required line in slope intercept form is


y = - (1)/(3) x + c {Where c is a constant}

Now, this above equation passes through the point (-9,2) point.

So,
2 = -  (1)/(3) * (-9) + c

⇒ 2 = 3 + c

c = - 1

Therefore, the equation of the required straight line is
y = - (1)/(3)x - 1 (Answer)

User Dan Harrington
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