Question

A solenoid 2 cm long consists of 5653 loops of wire. If the magnetic field inside the solenoid is 4 T, what is the magnitude of the current that flows through it? A solenoid 2 cm long consists of 5653 loops of wire. If the magnetic field inside the solenoid is 4 T, what is the magnitude of the current that flows through it? 140 A 9.1×10−2 A 11 A 2.0 A

Answer 1

11 A

Step-by-step explanation:

The magnetic field inside a solenoid can be calculated by the equation:

B = μ*(N/L)*i

Where B is the magnetic field, μ is the magnetic permeability (which is 1.256x10⁻⁶ T/m.A at vacuum), N is the number os loops, L is the length of the solenoid (2 cm = 0.02 m), and i the current.

4 = 1.256x10⁻⁶ *(5653/0.02)*i

0.355i = 4

i ≅ 11 A