Question

A 47.0 kg uniform rod 4.25 m long is attached to a wall with a hinge at one end. The rod is held in a horizontal position by a wire attached to its other end. The wire makes an angle of 30.0 ∘ with the horizontal, and is bolted to the wall directly above the hinge.

If the wire can withstand a maximum tension of 1350 N before breaking, how far from the wall can a 69.0 kg person sit without breaking the wire?

Answer 1

2.79 m

Step-by-step explanation:

Use the static equilibrium condition, net torque actin on the system is zero.

`\sum \tau= 0`

`T(Lsin\theta)- Mg(L)/(2)-mgx=0`

solve for the distance of the person from the wall x

`x= (TLsin\theta-Mg(L/2))/(Mg)`

now putting the values we get

`x= (1350*4.25sin30-47*9.81*(4.25/2))/(69*9.80)`

= 2.79 m