Question

It's urgent please help​

Answer 1

The equation of line is 2x-3y=15.

Explanation:

Given;

Slope is 2/3 and crosses y axis at (0,-5).

Now, the point = (0,-5) that is
`(x_(1),y_(1))` and the slope of the line = 2/3 which is
`m`.

So, now putting the formula for the equation of the line:

`y-y_(1) =m(x-x_(1))`

`y-(-5)=(2)/(3)(x-0)`

`y+5=(2)/(3)(x-0)`

On solving equation we get :

`3y+15=2x-0`

`15=2x-3y`

`2x-3y=15`

Therefore, the equation of line is 2x-3y=15.