Answer:
The magnitude of the linear acceleration of block A is 1.21 m/s² in downward.
Step-by-step explanation:
Given that,
Mass of block A = 6.00 kg
Mass of block B = 3.00 kg
Moment of inertia = 0.220 kg.m²
Radius = 0.120 m
Suppose we need to find the the magnitude of the linear acceleration of block A
Let a is the acceleration of the blocks.
Let
and
are the tension in the A and B cord.
According to figure,
We need to calculate the magnitude of the linear acceleration of block A
Net force acting on block A,


...(I)
Net force acting on block B,


...(II)
Net torque acting on pulley








Put the value into the formula


Hence, The magnitude of the linear acceleration of block A is 1.21 m/s² in downward.