Question

the radius of the aluminum atom is 143pm. the radius of the aluminum atom is 54pm. by what percentage did the radius change as the ion formed?

Answer 1

There was 62.23% change in radius as the ion formed.

Explanation:

Given

Radius of Aluminium
`(Al)` atom = 143 pm

Radius of Aluminium
`(Al^(3+))` atom = 54 pm

Change is the radius = Radius of Aluminium
`(Al)` atom - Radius of Aluminium
`(Al^(3+))` atom = 143 -54 = 89

Now to find % Change is the radius we will divide Change is the radius by Radius of Aluminium
`(Al)` atom and multiply by 100 we get

% Change is the radius =
`\frac{\textrm{Change is the radius}}{\textrm{Radius of Aluminium (Al) atom}} * 100 = (89)/(143)*100= 62.23\%`

Hence there was 62.23% change in radius as the ion formed.